JAVA program to find maximum between three numbers using ternary operator

In this JAVA program we find maximum between three numbers using ternary operator. For eg 11,21,12 the maximum of these numbers is 21.

So 21 should be as output.

Ternary operator :- condition?true:false

For eg  a<b?System.out.println(a):System.out.println(b)

Logic

Ternary Operator is used in the following way condition?true:false.

Dry Run of the Program

We have taken 3 integer variables  a,b and c.

Let us say a=11 , b=21,c=12

temp = a>b?a:b;   i.e. temp = a(11)>b(21) ? a(11):b(21)

As a is less than b, hence it is false and b is stored in temp variable;

max = temp>b?temp:b;

max = temp(21)>c(12) ? temp(21):c(12)

As temp is greater than c , hence it is true and temp is stored in max variable;

So then we print the output as maximum is 21.

Program

import java.util.*;

class maxTernary {
    public static void main(String args[]) {
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter the first no");
        int a = sc.nextInt();
        System.out.println("Enter the second no");
        int b = sc.nextInt();
        System.out.println("Enter the third no");
        int c = sc.nextInt();
	int max,temp;

	temp = a>b?a:b;
	max = temp>b?temp:b;
        System.out.println("Maximum of the three numbers is "+max);	
   }
}

Output